12x^2+7x-20=-4x-5

Solution for 12x^2+7x-20=-4x-5 equation:

12x^2+7x-20=-4x-5

We move all terms to the left:

12x^2+7x-20-(-4x-5)=0

We get rid of parentheses

12x^2+7x+4x+5-20=0

We add all the numbers together, and all the variables

12x^2+11x-15=0

a = 12; b = 11; c = -15;
Δ = b2-4ac
Δ = 112-4·12·(-15)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-29}{2*12}=\frac{-40}{24}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+29}{2*12}=\frac{18}{24}
=3/4
$